Th | Pa NO - If 75.0 g Fe, O3 and 4.50 g H, react according to the following equation how many grams of water can w...

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science chemistry

Answer 1

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Answer #1

predict the limiting reagent first

according to balanced reaction

159.69 g Fe2O3 reacts with 2 x 2 g H2

75.0 g Fe2O3 reacts with 75.0 x 2 x 2 / 159.69 = 1.88 g H2

but we have 4.50 g H2.

so H2 is excess reagent

limiting reagent = Fe2O3

now

159.69 g Fe2O3 gives 3 x 18 g H2O

75.0 g Fe2O3 gives 75.0 x 3x 18 / 159.69 = 25.4 g H2O

mass of H2O formed = 25.4 g

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Answer 2

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