Question

In this question you will write two functions that print a rainbow with at most 5 different colours. A rainbow of size n (n>=1) has n+1 rows and (n*4)+2 columns following the pattern below. Sample Output: rainbow(1) rainbow (2) rainbow(3) rainbow(4) RRRRRRRR RRRRRRRRRR RRRR RRRRRR R YYYYYY oVCCCC RY ve R RYG cYR RYGBBBBBBВВBBGYR RYGB BGYR In the above examples, the chars 'R','Y','G', 'B' and 'P' are the colour characters that are used to draw the stripes of the rainbow order (from the outside moving is of size greater than 5, repeat the 5 colours in order. Note in the above examples, there are no spaces after the last R in each row and there is a lin after each row Write a function rainbow with a single int size parameter and five char colour character parameters and outputs (prints) the corresponding rainbow. Your implementation for this part must only use while loops.

Answer 1

RRRR def rainbow(n): colors "RYGBP" RRRRRR count = RYYYYYYR RY YR while count n: RRRRRRRR colors [count] line colors[:count+1] colors[:count+1][:: -1] (n-count) - RYYYYYYYYR * (2*n) + RYGGGGGGGGYR line = line RYG GYR count + 1 print (line) RRRRRRRRRR RYYYYYYYYYYR RYGGGGGGGGGGYR print(colors[:count] (2*n+2) + BBG RYGBBBBE colors [:count][:-1]) RYGB BGYR for i in range (1,5): rainbow(i) print)

def rainbow(n):

colors = "RYGBP"

count = 0

while count < n:

line = colors[:count+1] + colors[count]*(2*n) + colors[:count+1][::-1]

line = ' '*(n-count) + line

count += 1

print(line)

print(colors[:count] + ' '*(2*n+2) + colors[:count][::-1])

for i in range(1,5):

rainbow(i)

print()