




Initial mass of methyl benzoate = 3.4 gms
Molar mass of methyl benzoate = 136.15 g/mol
No. of moles of methyl benzoate = Mass/molar mass = 3.4 g/136.15 g/mol = 0.02497 moles
We can observe in the above nitration reaction the molar ratio of methyl benzoate and meta nitro methyl benzoate is 1:1
Similarly the molar ratio of methyl benzoate and para nitro methyl benzoate is 1:1
Molar mass of meta nitro methyl benzoate / para nitro methyl benzoate is 181.15 g/mol
Hence moles of meta nitro methyl benzoate / para nitro methyl benzoate = 0.02497 moles
Theoretical Mass of meta nitro methyl benzoate / para nitro methyl benzoate = moles x molar mass = 0.02497 mol x 181.15 g/mol = 4.524 g
Percentage yield of product 1 (meta nitro methyl benzoate) = (actual yield/theoretical yield) x 100 = (3.9155g/4.524 g) x 100 = 86.5 %
Percentage yield of product 2 (para nitro methyl benzoate) = (2.1999 g/4.524 g/mol) x 100 = 48.6 %
the weight if the initial product was 3.4 grams of methyl benzoate. Who |o yald foR 3.91SSg st prodoc...
For the nitration of methyl benzoate:
a. Which product did you get? What evidence do you have for
this?
b. Was your product pure? What evidence do you have for this?
Explain your evidence.
c. Draw the mechanism for the product you got.
For the bromination of acetanilide:
a. Which product did you get? What evidence do you have for
this?
b. Was your product pure? What evidence do you have for this?
Explain your evidence.
c. Draw the mechanism...
Nitration of Methyl Benzoate to synthesize Methyl m-nitrobenzoate Find theoretical yield and percent yield. Show all steps. Results: .040 g of methyl m-nitrobenzoate crystals produced 1. Add .30 g of Methyl Benzoate to .6 ml of Sulfuric Acid in a reaction tube 2. Dropwise add a mixture of .2 ml of sulfuric acid and .2ml of nitric acid 3. After 15 min, pour onto 2.5 g of ice in a small beaker 4. Use suction filtration to dry crystals. Wash...
numbers 1-3
Post-Laboratory Questions-EXP 3 Nitration of Aromatic Compounds Name: Due after completing the lab. 1. Why is concentrated sulfuric acid emploved in thie on? What is the electrophile that is produced by the reaction of sulfuric acid and nitric acid? 2. Why is it important to maintain the reaction temperature low and the addition of nitric acid-sulfuric acid mixture carried out slowly? 3. Explain why concentrated H2SO4, not concentrated HC1, was used in this experiment? 4. Which ring of...
3-5 pls
Post-Laboratory Questions-EXP 3 Nitration of Aromatic Compounds Name: Due after completing the lab. 1. Why is concentrated sulfuric acid employed in this reaction? What is the electrophile that is produced by the reaction of sulfuric acid and nitric acid? 2. Why is it important to maintain the reaction temperature low and the addition of nitric acid-sulfuric acid mixture carried out slowly? 3. Explain why concentrated H2SO, not concentrated HCl, was used in this experiment? 4. Which ring of...
Complete the table of reactants and products for the following two reactions. Compound Molar Mass (g/mol) Mass Volume Density (g/mL) # Mols Equivalents of Reactants (divide actual moles by stoichiometric moles) Other (indicate which is limiting reactant) Nitration of Methyl Benzoate In a 50 mL Erlenmeyer flask, cool 6 mL of conc. H2SO4 in ice and add 3.0 g of methyl benzoate. Make sure the temperature stays at 0 oC . Using a pipet, slowly add a cooled mixture of...
PROCEDURE CAUTION!!! Nitric acid and sulfuric acid are strong and corrosive acids. For that reason, avoid inhaling its vapors or causing any contact with the skin or clothing. Wear your protective glasses at all times. Use the extractors to work with these acids. A. Nitration of methyl benzoate 1. Preparation of the reactants. In the extractor you will find a burette with concentrated sulfuric acid, a second burette with concentrated nitric acid, clearly identified. Familiarize yourself with the scales of...
-NITRATION OF Methyl benzoate
-addditional information. .( 3.9 g of the product methyl
3-nitrobenzoate for the percentage yield
Materials used: Amount Compound used/ Molecular weight Density (g/mL) Moles produced 3.05g used 136.15 g/mol N/A 0.0224 mol Methyl Benzoate HO-S-OH 6mL used 98.079 g/mol 1.83 g/cm3 0.112 Sulfuric Acid 2mL used 63.01 g/mol 1.51 g/cm3 0.047g o-N-OH Nitric Acid 3.034g of pure product 181.15 g/mol produced N/A 0.0167 mol NO2 Methyl-m- nitrobenzoate Calculating limiting reagent and theoretical yield: 0.0224 mol methylbenzoate...
What is the limiting reagent in this experiment? Acetophenone or
aqueous bleach?
1. Add about 1.0 g (measured accurately) of acetophenone to 40 mL of the bleach solution (5% NaCl in water - this reactant should be included in your table of reagents!) in a 100 mL round bottom flask equipped with a magnetic stirrer. Clamp the flask in the fume hood above a stir plate. 2. After the initial reaction has subsided, boil the reaction mixture gently for 5...
How does the acetone destroy
the unreacted hypochlorite?
1. Add about 1.0 g (measured accurately) of acetophenone to 40 mL of the bleach solution (5% NaCl in water - this reactant should be included in your table of reagents!) in a 100 mL round bottom flask equipped with a magnetic stirrer. Clamp the flask in the fume hood above a stir plate. 2. After the initial reaction has subsided, boil the reaction mixture gently for 5 - 10 minutes using...
What is the mechanism (with
curved arrows) for this reaction?
1. Add about 1.0 g (measured accurately) of acetophenone to 40 mL of the bleach solution (5% NaCl in water - this reactant should be included in your table of reagents!) in a 100 mL round bottom flask equipped with a magnetic stirrer. Clamp the flask in the fume hood above a stir plate. 2. After the initial reaction has subsided, boil the reaction mixture gently for 5 - 10...