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of 10 > A 37.0 mL aliquot of a 0.400 M stock solution must be diluted to 0.100 M. Assuming the volumes are additive, how much
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Answer #1

A 1 L solution of 0.4M stock contains 0.4 moles

37 ml of the same stock would contain: 0.037* 0.4 = 0.0148 moles

These 0.0148 moles need to be diluted to 0.1M

Volume = moles / molarity = 0.0148 / 0.1 = 0.148 L = 148 mL

Water to be added : 148 - 37 = 111 mL

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