

Score 2. (22 points) For the circuit in Figure 2, the transistor parameters are: 2 0,...
1-Clear handwriting
2-Correct answer
3-Organized
4-answer all the questions
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Problem 2 On the circuit on Figure P2, transi stor Q1 has a threshold voltage of Vt = 2 V and a transconductance parameter of k = 100 mA/V2. Note that Vcc = -Vee = 4.5 V. Moreover, capacitors C1, C2, and C3 can be assumed to be very large VDD 4.5.0 R3 25kQ R1 300kn C2 Vout C1 Rsig Q1 1k0 R2 200kn Vsig (R4 2kQ C3 -4.5V VSS...
Q5 Figure 4 is a common-source circuit. The PMOS transistor parameters are VTP = -0.6V, Kp = 1mA/V and 1 = 0. Assume the transistor is biased in saturation such that Ipo = 0.25mA and Vspo = 1.5V. a) Find Rs and RD- b) Draw the small signal ac equivalent circuit. c) Determine the circuit's input resistance (R.), output resistance (Rour) and small signal voltage gain (Av) Figure 4 = 100k2 RO
Problem 2 Consider the feedback amplifier circuit on Figure P2. The DC current gain of transistor Q3 is -100 1. What type of feedback (or what feedback topology) do we have on the circuit in Figure P2? 2. Draw the A-circuit. Express and compute the open-loop voltage gain A at mid-band frequency 3, Draw the γ-circuit. Express and compute the feedback factor γ 4. Express and compute the overall gain of the feedback amplifier Ap Express and compute the input...
Q2)
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Question 2 (25 Marks) (a) (6 Marks) Bias the CE amplifier in Figure 2 to have IE = 1mA. Assume B-100, VBE(On) = 0.7 V, Vcc = 15V, VEE= -15V and RB = 100kQ. List all node voltages, currents and resistor values. (b) (10 Marks) Draw the small-signal model for the CE amplifier in Figure 2 Determine the input resistance, output resistance and gain of the amplifier. Assume VA = 100V, RL...
Assuming an ideal op-amp in the following circuit, find output voltage, Vo if R1= 2 K2, R2=8 K2, R3=5.1 K2, R4=6 KN, R5=14 KN, R6=4.2 KS, RL=10.3 KS, V1=1V, 12=0.5 mA and V3=3.2 V. R6 R1 R5 Vo w + * RL + 12 R2 V1 R3 R4 V3 Answer: OV Using the above circuit, but consider the following component values: R1= 2 K12 R2=8 K2, R3=2.9 K2, R4=6 KI2, R5=10.8 K92, R6=15 KO, RL=10 K2, V1=1V, 12=0.5mA and V3=2V....
Assuming an ideal op-amp in the following circuit, find output voltage, Vo if R1= 2 K12, R2=8 KN, R3=3.9 KN, R4=6 KN, R5=18 K2, R6=4.4 KN, RL=12.5 KN, V1=1V, 12=0.5 mA and V3=3.4 V. R6 R1 R5 Vo + + RL R2 V1 R3 R4 + V3 Answer: LOV Using the above circuit, but consider the following component values: R1= 2 KO2 R2=8 K12, R3=3.6 K12, R4=6 K12, R5=16.9 KN, R6=15 KN, RL=10 KO, V1=1V, 12=0.5mA and V3=2V. What is...
Assuming an ideal op-amp in the following circuit, find output voltage, Vo if R1= 2 K2, R2=8 K12, R3=3.8 KS2, R4=6 KI2, R5=15 KS2, R6=3.8 KN, RL=9.8 K12, V1=1V, 12=0.5 mA and V3=2.2 V. } R6 R1 w R5 w + Vo + } RL 12 R2 V1 R3 R4 + +1 V3 Using the above circuit, but consider the following component values: R1= 2 KN R2=8 K2, R3=4.1 K12, R4=6 KI2, R5=17.0 K12, R6=15 KI, RL=10 KI, V1=1V, 12=0.5mA...
In the circuit of the figure, the bipolar transistor has a B =
25 and the MOSFET has a VTN = 2V as well as a conduction parameter
Kn = 1mA / V ^ 2. Determine the value of the input voltage required
for the output voltage Vo = 15V.
+24V Vztav 1k Vi 2k Tuin Figura 4
IV, Laboratory Procedure 1. Construct the circuit of Figure 6.1, measure the current value 2. Construct the circuit of Figure 6.2; measure Vn and v., using the oscilloscope. 3. Construct the circuit of Figure 6.3, measure the value of Io and V 4. Construct the clipper design circuit, Capture the input and output waveforms. 5. Construct your clamper design circuit. Capture the input and output waveforms Figure 6.3 Design a clipper circuit which limits input signals to +3V and -2V....
F LOpoint For the circuit shown in Figure 3 3. 1. Draw the DC equivalent circuit by opening caps and shorting inductors 2. Analyze the DC equivalent circuit as we have in previous labs (assume a region, analyze and check assumptions). Check your DC operating point using LT Spice. 3. Calculate the small signal parameters (transconductance, output resistance, input resistance) 4. Draw the AC equivalent circuit by shorting de voltage sources, opening dc current sources, shorting caps and opening inductors....