Question

Identify the compound with the higher boiling point in each of the following pairs of compounds: 1. CH2-CH2-OH or H--C--0--CHz OH 2. CHz---0-CH3 or CH3-CH-CH2-CH3 0 2, CH, -- pH 3. CHz--2-0-CH, or CH3-CH2-CH2-CH2-CH3 Write the products of hydrolysis or saponification for the following esters. н" 1. CH3-CH-CH2--0--0--CH3 + H2O O 2, CH4-C-0-CH + NaOH 3. O -8-6-CH2-CH; -CH ---CH3 + KOH — -0--CH-CH2-CH3 + H20 -

Answer 1

Boiling point depends upon intermolecular forces and weight of molecule. for molecules having similar mass: Boiling point order is : Intermolecular strength Alcohols > Esters > Alkanes Forces Hydrogen-bonding > Dipole-Dipole) London forces 10. 1.1. CH₂ - CH₂-OH) H O-CH3 2. CH3 – 8-0-cts < CH₂ – CH – CH2=CH² 3. CH₂ - 2-0 - CH₂ > CH3 - CH₂ - CH2 - CH2-CHg 11. 2. colg- CH2 - CH₂ -2-0-CH3 + H₂O 4th - CH₂ - CH2 CH₂ - E-OH + HO-CH3 2. CH₂ -8- 0-CH3 + NaOH - CHS- & - o- Mat & HO-CH3 3.0 l-o-chz-CH3 + KOH-> 0-1-ok + HO-CHA-CHE E-O-CH₂-CH₂ - CH2 + H₂O 14t -c-OH + HO-CH₂-CH ₂ -CH 3