Question

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1. Determine the trend for each property (i.e. whether it increases or decreases): Across a row of the Down a column in the PT PT? Size Ionization energy Electron affinity 1. Within a given row, which Group of elements has the greatest atomic size? (a) The alkali metals (b) The halogens (c) The noble gases (d) Another Group (give the Group number using the IUPAC system) 2. Within a given row, which Group of elements has the smallest atomic size? (a) The alkali metals (b) The halogens (e) The noble gases (d) Another Group (give the Group number using the IUPAC system) 3. Within a given row, which Group of elements has the greatest ionization energy? (a) The alkali metals (b) The halogens (e) The noble gases (d) Another Group (give the Group number using the IUPAC system) 4. Within a given row, which Group of clements has the greatest ionization energy? (a) The alkali metals (b) The halogens (c) The noble gases (d) Another Group (give the Group number using the IUPAC system) 5. Within a given row, which Group of elements has the greatest electron affinity? (a) The alkali metals (b) The halogens (c) The noble gases (d) Another Group (give the Group number using the IUPAC system)

Answer 1

	Across the Row of PT	Down a column in PT
Size	Decreases	increases
Ionisation energy	Increases	Decreases
Electron affinity	Increases	decreases

2. Within a row which group of elements has the greatest atomic size.

Answer: Alkali Metals.

3. Within a row which group of elements has the smallest atomic size.

Answer: Noble Gases

4.Within a row which group of elements has the greatest ionisation energy

Answer: Noble Gases

5.  Within a row which group of elements has the greatest electron affinity

Answer:halogens

6a

$Li \rightarrow Li\oplus + e \circleddash$. THe electron is removed from 2 S orbital for Lithium

6b

$Na\rightarrow Na\oplus + e \circleddash$ The electron is removed from 3S orbital for Sodium

6C

Sodium has three orbits and LIthium has two orbits. HIgher the distance from the nucleus, lesser the energy required to remove the proton. Hence the ionisation energy is lesses for sodium than LIthium

7a

$Cl + e\circleddash \rightarrow Cl\circleddash$. The electron is added to 3p orbital

7b

$Ar + e\circleddash \rightarrow Ar\circleddash$. The electron is added to 3d orbital.

.7C)

The electron affinity is more for chlorine as the electron is completely filled in 3P orbital and gets stabilized. Argon adds up the electron to the new orbital and moves from stable form to unstable one.