Explain why it is generally more preferred to use a three-electrode system (composed of working, counter, and reference electrodes) than a two-electrode system in electrochemical analysis. Also explain the role of working, counter, and reference electrodes, respectively, in a three-electrode system.
# Three electrode system is preferred over Two electrode system, Why?
The electrochemical reaction depends on its thermodynamic property, which is reflected by the electrode potential rather than the voltage according to Nernst equation. Therefore, the three-electrode system is preferable.
# Roles of the electrode:
The three-electrode system consists of a working electrode, counter electrode, and reference electrode.
Explain why it is generally more preferred to use a three-electrode system (composed of working, counter,...
9. (a) Describe the difference between galvanic and electrolytic cells (5 pt) (b) Explain why it is generally more preferred to use a three electrode system (composed of working, counter, and reference electrodes) than a two electrode system in electrochemical analysis. Also explain the role of working, counter, and reference electrodes, respectively, in a three electrode system. (10 pt)
9. (a) Describe the difference between galvanic and electrolytic cells (5 pt) (b) Explain why it is generally more preferred to...
b) Electrochemistry is the branch of physical chemistry that
studies the relationship between electricity, as a measurable and
quantitative phenomenon, and identifiable chemical change, with
either electricity considered an outcome of a particular chemical
change or vice versa. These reactions involve electric charges
moving between electrodes and an electrolyte (or ionic species in a
solution). Thus electrochemistry deals with the interaction between
electrical energy and chemical change. When a chemical reaction is
caused by an externally supplied current, as in...
Explain why three phase and not two phase circuits and machines are the preferred choice in industrial applications?
As we considered in the class conjugation is generally more effective in the para position than meta. Consider two electron-donating groups: -NH2 and -OCH3. For -OCH3 group spara and smeta values are to -0.29 and 0.11, respectively. For amino group, however, spara = -0.62 and smeta = 0.00. Explain the following observations below. Draw the structures to support your answer. a) Why is smeta value more positive than spara? b) How would you explain smeta = 0.00 for -NH2 group?
As we considered in the class conjugation is generally more effective in the para position than meta. Consider two electron-donating groups: -NH2 and -OCH3. For -OCH3 group spara and smeta values are to -0.29 and 0.11, respectively. For amino group, however, spara = -0.62 and smeta = 0.00. Explain the following observations below. Draw the structures to support your answer. a) Why is smeta value more positive than spara? b) How would you explain smeta = 0.00 for -NH2 group?
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