The formation constant for [Cu(NH3)4]2+ is 5.00 × 1012. What is the equilibrium expression for this...
The formation constant for [Cu(NH3)4]2+ is 5.00 × 1012. What is the equilibrium expression for this value?
Group of answer choices
Kf = 1/[[Cu(NH3)4]2+]
Kf = [Cu2+][NH3]4/[[Cu(NH3)4]2+]
Kf = [Cu2+][NH3]/[[Cu(NH3)4]2+]
Kf = [[Cu(NH3)4]2+]/[Cu2+][NH3]4
Kf = [[Cu(NH3)4]2+]/[Cu2+][NH3]
Kf = [[Cu(NH3)4]2+]
Homework Answers
formation constant for [Cu(NH3)4]2+ = 5.00 × 1012
balanced equation :
Cu2+ (aq) + 4 NH3 (aq) ------------> [Cu(NH3)4]2+
equilibrium expression :
Kf = [ [Cu(NH3)4]2+] / [Cu2+] [NH3]4
Answer :
Kf = [[Cu(NH3)4]2+]/[Cu2+][NH3]4
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