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66. A student needs 500 ml of SOM HC solution. How much in ml, of concentrated HCl is required to prepare this solution Conce
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Answer #1

66) Using M1V1(conc. HCl) = M2V2 (HCl solution)

12.0×V1 = 0.50×500

V1 = 250/12

= 20.83 ml

67) At equivalence point,

Moles of NaOH = moles of KHP = mass of KHP/molar mass

= 1.221/204.22 = 0.00598 moles

Concentration of NaOH = moles×1000/volume

= 0.00598×1000/80

= 0.0747 M

68) HCl(aq) + NaOH (aq) \rightarrow NaCl(aq) + H2O (l)

69) Ba(OH)2(aq) + H3PO4 (aq) \rightarrow Ba3(PO4)2(s) + H2O(l)

Balanced equation :

3Ba(OH)2(aq) + 2H3PO4(aq) \rightarrow Ba3(PO4)2(s) + 6H2O(l)

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