Question

c. We can convert the right tail area o 276 L02) to a left-hand area of 1.0-.02-.98, or 98%. (See the picture to the right.) The z-score for an area of .9800 is 2.05 (actually, this corresponds to the area closest to .9800 in the table-9798). We'll set the marker, then, 2.05 standard deviations above the mean. Since a standard deviation here is 10 days, this means we'll set the mark at 120+ 2.05(10) 140.5 days. 9800 120 0 19. In Exercise 16, we saw the following situation: Harada Construction has just bid on a major com- mercial project. The bid was based on a normal dis- tribution representing Harada's estimates of possible costs for the project. The distribution is centered on $6.5 million and has a standard deviation of $1.1 21 million. According to Harada's estimates: a. There is a 60% chance that costs will be less b. There is a 1 % chance that the cost will be greater c. There is a 45% chance that costs will be between million the lower boundary for your interval.) than $ than $million. $6.5 million and $ million million. (Make $6.5 0. Metropolitan Power and Light (MPL) tracks peak d in gigawatts (GW), for its

Answer 1