Homework Answers
In a given cross between two heterozygote AaBbCcDdEe we get in first generation following
Probability of getting Aa = 1/2
Probability of getting AA is = 1/4
Probability of getting BB is = 1/4
Probability of getting Bb is = 1/2
Probability of getting CC is = 1/4
Probability of getting Cc is = 1/2
Probability of getting dd is 1/4
Probability of getting ee is 1/4
Probability of getting phenotype ABCde or genotype A_B_C_ddee can be calculated by forked line method
In which probability of getting :
- AABBCCddee will be 1/4x1/4x1/4x1/4x2/4= (1/4)5
- AaBbCcddee will be 1/2x1/2x1/2x1/4x1/4= (1/2)3 (1/4)2
- Similarly for other genotypes individual probability can be multiplied as given above and particular genotype can be arrived at .
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