For the reaction: 2HBr(g) + Cl2(g) -----> 2HCl(g) + Br2(I) a) calculate delta G for this...

Question

Question

For the reaction: 2HBr(g) + Cl2(g) -----> 2HCl(g) + Br2(I)

a) calculate delta G for this reaction using free energy values.

b) Calculate delta G at standard temperature when pressure of HBr is 4.97 atm, Cl2 is 3.56 atm and HCl is 2.18 atm.

c) Calculate Kp for this reaction.

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Answer 1

Answer #1

For the reaction: 2HBr(g) + Cl₂(g) -----> 2HCl(g) + Br₂(I)

(a) calculate ▵G for this reaction using free energy values.

$4G = [24_G°(HCI) +4_Gº(Br)]-[24_Gº (HBr) - 4 Gº(C7)] ={[2x–95.27]+3. 14)+2x53.22 =-80.96 KJ/mol$

(b) Calculate ▵G at standard temperature when pressure of HBr is 4.97 atm, Cl2 is 3.56 atm and HCl is 2.18 atm.

(c) Calculate K_p for this reaction.

K_p = p_HCl² / p_Cl2 x p_HBr²

K_p = 2.18² / 3.56 x 4.97²

K_p = 4.7524 / 87.935 = 0.054

▵G = ▵G^o + RTln K_p

▵G^o = ▵G - RTln K_p

▵G^o = -80.96 KJ - 8.314 x 298 x ln0.054

▵G^o = -80.96 KJ +7.231 KJ = - 73.73 KJ

Answer 2

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