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How many milliliters of a 0.300M calcium chloride solution is required to prepare 650.0mL of 0.0500M...

How many milliliters of a 0.300M calcium chloride solution is required to prepare 650.0mL of 0.0500M solution?

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Answer #1

By using relation, M, U = M2 V₂ 2 O. 00M X U = 0. 0500 M X 650mL * v= 1108.33mL) = volume needed

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