(a)
Mass flow rate of water,
m =
* volume flow rate
m = 1000 * 64*10-3 = 64 kg/s
Change in mechanical energy of fluid,
E
= m [(P2 - P1 /
) + (V22 - V12 / 2) + g(h2 - h1)]
E
= 64 [0 + 0 + 9.8*(18 - 0)]
E
= 11289.6 W = 11.28 kW
Efficiency of pump motor unit,
=
E / W = 11.28 / 21.2
= 0.5325
= 53.25 %
(b)
Pressure b/w inlet and the exit of the pump,
P
=
E
/ volume flow rate
P
= 11.28 / 64*10-3
P
= 176.4 kPa
Storage tank 18 m Pump Water is pumped from a lake to a storage tank 18...
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