HomeworkLib
Question

Three compounds, octane, nonane, and an unknown molecule, were separated using gas chromatography. The adjusted retention...

Three compounds, octane, nonane, and an unknown molecule, were separated using gas chromatography. The adjusted retention times were 14.1 min for octane, 21.5 min for nonane, and 19.0 min for the unknown. The retention indexes for the alkanes are 800 for octane and 900 for nonane. Calculate the Kovats retention index for the unknown.

I = ____

science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

Thoz tr CN Aog14-1 8t (9-8) l0319 21-5degi X o.70699 8 T 100 I > 87O

0 0
Add a comment
Know the answer?
Add Answer to:
Three compounds, octane, nonane, and an unknown molecule, were separated using gas chromatography. The adjusted retention...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • Calculate the Kovats retention index for an unknown using the retention times 1.5 min for CH,,...

    Calculate the Kovats retention index for an unknown using the retention times 1.5 min for CH,, 12.7 min for octane, 14.3 min for the unknown, and 18.7 min for nonane. T =

  • EXERCISE 6: Two chemical species, A and B are separated by isothermal gas chromatography, using a...

    EXERCISE 6: Two chemical species, A and B are separated by isothermal gas chromatography, using a 2.00 m column having 5000 theoretical plates at a flow rate of 15.0 ml / min. The peak of unabsorbed air appears after 30 s; the peak of A appears after 5 min and that of B after 12 min (a) Calculate the dead volume VM of the column, and the retention volumes Va and VB. (b) Calculate the reduced volumes V’a and V'B...

  • Species 1, 2, 3, and 4 were separated using gas chromatography (species 1 is the solvent)....

    Species 1, 2, 3, and 4 were separated using gas chromatography (species 1 is the solvent). Answer the following multiple choice question based on the chromatogram shown below. Which of the following statements are true regarding the chromatogram shown above? At t = 8 min, there is more of species 1 in the stationary phase compared to species 4. Species 4 has the highest partition coefficient. At t = 8 min, there is more of species 4 in the stationary...

  • Table 2: Alcohol and Ketone Standards GC Retention Times GC#: Retention time Alcohol Standard Mixture Phent...

    Table 2: Alcohol and Ketone Standards GC Retention Times GC#: Retention time Alcohol Standard Mixture Phent ion= 2.05Smin low Peak 1 Compound Name: athanol Rapesnal utanal aclapeatanal 4.755min oilng 6.895min .230 min Peak 2 Compound Name: Peak 3 Compound Name: Peak 4 Compound Name: GC#:1 Ketone Standard Mixture Retention time 2.575un Peak 1 Compound Name: Acclono Butanon a Pentanone 2tHex anon Peak 2 Compound Name: min Peak 3 Compound Name: 615 min 1D. 307 min Peak 4 Compound Name: Part...

  • 2. If two different compounds have the same Rr value, how might they be identified using paper chromatography?...

    2. If two different compounds have the same Rr value, how might they be identified using paper chromatography? 3. Why is it important to keep the spots on the paper as small as possible? 4. If the solvent pool at the bottom of the beaker touched the spots on the 1.5cm line, what would happen to the spots? How would you address this error? 5. If you were teaching a student how to do paper chromatography, what three pieces of...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT