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A 2.78 L aqueous solution of KOH contains 183 g of KOH. The solution has a density of 1.29 g/mL. Calculate the molarity (M),

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Answer! VIL) = 1.17 mol Marity = n m. nz Moles of kon = 183g 5681 mol v=valume of solution Malarity = 1.17 M 9-78 Molarity

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