
write answer step by step on the paper
write answer step by step on the paper What would you expect to see if you...
Using R output provided
1). Perform hypothesis testing for B(beta)1=2 using
A(alpha)=0.05
> summary(ls) Call: Residuals: Min 1Q Median 3Q Max 0.20283 -0.14691 -0.02255 0.06655 0.44541 Coefficients: (Intercept) 0.365100.099043.686 0.003586 ** Signif. codes: 0 '***' 0.001 '0.01 '*'0.05 '.' 0.1''1 Estimate Std. Error t value Pr>Itl) 0.96683 0.18292 5.286 0.000258** Residual standard error: 0.1932 on 11 degrees of freedom Multiple R-squared 0.7175, Adjusted R-squared: 0.6918 F-statistic: 27.94 on 1 and 11 DF, p-value: 0.0002581 anovaCLs) Analysis of Variance Table Response:...
What are the implications of predictability results in Part 2 and 3 for investment decisions? Part 2 use log dividend-price ratio to predict the 5-year stock market excess log returns: lm(formula = lnexret[2:t] ~ dp[1:t - 1]) Residuals: Min 1Q Median 3Q Max -0.54389 -0.07305 0.01977 0.10712 0.34107 Coefficients: Estimate Std. Error t value (Intercept) 0.58469 0.12768 4.579 dp[1:t - 1] 0.13510 0.03771 3.582 Pr(>|t|) (Intercept) 1.58e-05 *** dp[1:t - 1] 0.000567 *** --- Signif. codes: 0 ‘***’ 0.001 ‘**’...
Analysis of Variance Table Response: Price Df Sum Sq Mean Sq F value Pr(>F) Living.Area 1 1.3501e+12 1.3501e+12 362.0394 < 2e-16 *** Bedrooms 1 2.3642e+10 2.3642e+10 6.3394 0.01241 * Fireplaces 1 7.6232e+07 7.6232e+07 0.0204 0.88642 Residuals 259 9.6588e+11 3.7293e+09 --- Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1 > Using= 0.05, perform an F test of overall linear relationship. State the hypotheses, the value of F-test statistic, p-value, and your conclusion.
The R code will help to answer
the question.
8. DeGroot&Shervish (2002) consider an experiment to study the combined effects of taking a stimulant and a tranquilizer. In this experiment three types of stimulant and four types of tranquilizer are administered to a group of rabbits. Each rabbit received one of the stimulants, then 20 minutes later, one of the tranquilizers. One hour later their response time (in microseconds) to a stimulus was measured. The results were: Tranquilizer Stimulant 1...
(a) Using the above t-test data to determine whether or not there
is a linear relationship between the two variables.
(b) Using the above ANOVA F-test data to determine whether or not
there is a linear relationship between the two variables.
(c) How do the results in (a) compare to those in (b)?
We were unable to transcribe this imageAnalysis of Variance Table Response: DatSGPA Dat $ACT 1 3. 588 3. 5878 9. 2402 0.002917 Df Sum Sq Mean sq...
A company manager is interested in analyzing the relationship between years of working experience and the salary of their employees. He has collected the data from 30 employees of their years of experience and the salary. Below provided is a partial regression output from R. Use the provided information to answer below questions Coefficients: (Intercept) YearsExperience Estimate Std. Error t value Pr(>ltl) 25792.2 2273.1 9450.0 --- Signif. codes: O '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1'' 1 Analysis of...
Using the built in data in R “ToothGrowth”. Why factor(does)
resulted in a different p-value using anova function.
headerH TRUE) 33 Corn <- factor(datal, 1]) 34 Yield <- datal, 21 35 Corn 36 table (Corn) 37 Yield 38 tapply(Yield, list (Corn) mean) group means 39 boxplot(Yield~datal,1]) 40 41 InsectSprays 42 table(InsectSprays) 43 Jungkook InsectSprays, 1] 44 Jungkook 45-Jin= InsectSprays [, 2] 46 Jin 47 boxplot (Jungkook-Jin) 48 49 pairwise.t.test(vield, Corn, pool.sd FALSE, p. adjust.method "none 50 Insectsprays 51 does 52...
> summaryCls) Call: Lm(formula y X) Residuals: -0.20283 -0.146910.02255 0.06655 0.44541 Coefficients: (Intercept) 0.36510 0.09904 3.686 0.003586 ** Min 1Q Median 3Q Max Estimate Std. Error t value Pr(>ltl) 0.96683 0.18292 5.286 0.000258*** Signif. codes: 00.001*0.010.050.11 Residual standard error: 0.1932 on 11 degrees of freedom Multiple R-squared 0.7175, Adjusted R-squared: 0.6918 F-statistic: 27.94 on 1 and 11 DF, p-value: 0.0002581 > anovaCls) Analysis of Variance Table Response : y Df Sum Sq Mean Sq F value PrOF) 1 1.04275 1.04275...
Q: indicate probability that all four groups of experiments
have the same mean and probability that group 2 and 3 have the same
mean.
Given the following outputs of anova analysis: summaryCaovCanxiety$'anxiety' anxiety$'stress' Df Sum Sq Mean Sq F value Pr(F) anxietySstress 3 182.1 60.70 11.94 5.56e-05 Residuals 24 122.0 5.08 Signif. codes: 0 0.001*0.01 *'0.05 '.' 01''1 > TukeyHSD aov(anxiety$'anxiety'~ anxiety$'stress' Tukey multiple comparisons of means 95% family-wise confidence level Fit: aov(formula = anxiety$anxiety ~ anxiety$stress) S' anxiety$stress ....
please provide the output in R
aov (hw labels) >summary (fit) > fit Df Sum Sq Mean Sq F value Pr(>F) 2 493.3 labels 246.7 5.763 0.0176 Residuals 12 513.6 42.8 Signif. codes: 0 0.001 0.01 0.05 0.1 1 12. For this problem, you will use R to conduct an ANOVA F-test. The R code from #11 should be useful for this problem. In #11, the dean only collected samples of size five from each engineering majors. Suppose he collects...