NMR: 2.82 shift (6H, singlet), 8.13 shift (4H, singlet) IR: 1681 1/cm, no OH stretch

Question

Question

NMR: 2.82 shift (6H, singlet), 8.13 shift (4H, singlet)

IR: 1681 1/cm, no OH stretch

science chemistry

Answer 1

Answer #1

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NMR:

2.82 shift (6H, singlet),---> two methyl groups (CH3)

8.13 shift (4H, singlet) ----> four identical hydrogens in the phenyl ring.

IR: 1681 1/cm, no OH stretch ---> carbonyl group (C=O)

Answer 2

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