Question

Please help with BOTH parts

[3] In a nuclear reaction, a proton (m, = 1.6726 x 10-25kg) and an electron (mass me = 9.11 x 10-51kg) collide and merge to form a neutron (mass m,- 1.6749 x 10-27kg), in a process known as inverse beta decay. (We are ignoring the effect of another particle called a neutrino that is also involved in the process.) (a) If the initial neutron and electron collide head-on as shown, what is the speed and direction (left or right) of the neutron after the collision? (b) Since the initial particles merge to form a new one, this process is totally inelastic. How much energy is lost? (Much of this energy goes into the kinetic energy of the particle we are ignoring: since the speeds are large, some of the energy goes into mass via Einstein's famous formula E = mc2.) Proton * 2 5X 10°miy - 3.0x 10 mg Electron Before Neutron After

Answer 1

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final kinutic mc 749x10-22(-1-6 /0) 94 1x.1o Sa tnung dss 4k.iKE 2 a 47x10 2:047 x10 941 x 10-/1 2.83 x10 lot