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ALOS = total length of stay for a given period/ total number of patient discharges for the same period
5. Create a control chart to show the ALOs by physician using the data below Number of patients Length of stay (in days) Physician Dr. Mellendorf Dr. Snodgrass Dr. Gunion Dr. Oliver Dr. Joyce Total 14 15 20 38 14 75 82 137 342 6. Theorize at least three reasons that the ALOS requirement was not met. 7. Based on the results illustrated on the control chart, predict which actions, if any, should be taken by the organization?
math   Statistics-And-Probability   
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Answer #1

Physicians <- c(Dr. Mellendorf, Dr. Snodgrass,Dr Gunion, Dr. oliver, Dr. Joyce No of_Patients <-c (14,15,20,38,14) Length of_stay<-c(75,82,137,342,88) Hospital <- data.frame (Physicians, No_of_Patients, Length of_stay) library (gicharts) ## qicharts wiïï no longer be maintained. Please consider moving to qīchart s 2: https://anhoej. github.io/qǐcharts qic (No_of_Patients main Control chart of No_of_Patients) Control chart of No_of Patients 35 30 2 25 20 15 CL-15 4 Subgroupgic(Length of stay, main Control chart of Length of stay Control chart of Length_of_stay 350 300 250 200 150 100 CL-88 4 Subgroupqic(Length of_stay/No_of_Patients, main Control chart of ALOS Control chart of ALOS 7 CL-6.3 4 Subgroup sum (Length_of_stay/No_of_Patients) ## [1] 32.95952 mean (Length_ofstay/No_of_Patients) ## [1] 6.591905ALOS is much higher than the mean ratio of no. of patients and length of stay but it certainly decreased frequently in the last observation as trend follows alos will get decrease. if organisation increasing the patients then they have to increase the stay also to gain profit statistically  

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