For Part 4, answer the following questions and fill out the table on the following page...
For Part 4, answer the following questions and fill out the table on the following page (You should have started with 1 mL of acid)
a. There are 20 drops in 1 mL. Calculate the volume (in Liters) of NaOH used for titrating each acid.
68 drops NaOH x 1ml/20 drops = 3ml x 1L/1000ml = 0.003 L NaOH
b. The concentration of sodium hydroxide is 0.10 M. Using the volume calculated in the previous step, calculate the moles of hydroxide anion used to titrate each acid.
0.003L x 0.10M/1L = 0.0003 mol -OH
c. Now, calculate the moles of hydronium cation that were present in each acid sample
0.0003 mol h+
d. Calculate the molarity of hydronium ion in each acid sample.
Homework Answers
d.
Volume of acid is 1 mL or 
This is also equal to volume of hydronium ion in each acid sample.
The number of moles of hydronium ion present in each acid sample are 0.0003 moles.
![[H3O+]= 0.0003 mol -= 0.3 M 0.001 L](http://img.homeworklib.com/questions/8e424620-4754-11ea-9f54-5334e5f6bfb2.png?x-oss-process=image/resize,w_560)
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For Part 4, answer the following questions and fill out the table on the following page...
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help;(
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Concentration of NaOH = 1600 x10- Molar Sodium hydroxide Nach Trial 1 Trial 2 Trial Trial 4 2.60/1.20 1...
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please help me answer 1-3. My avergae number of mL of 0.100M NaOH required to titrate...
please help me answer 1-3. My avergae number of mL of 0.100M
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CAMERY Review Layout References Mailings Wednesday, March 25, 2020 View Help ID Number Experiment 17: Analysis of an Antacid Normally in the lab we would do the titration as described. Instead I will be providing you with the results as if you had gotten them from your titration. The procedure calls for you to...
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PLS HELP THANK YOU
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Concentration of NaOH = 1600 x10- Molar Sodium hydroxide Nach Trial 1 Trial 2 Trial Trial...
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Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....
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Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
help;(
Data Sheet Titration and Buffers Name Date Part One: Buffer Solution (record the results from the video) Lab Section Number of Drops of HCl added to "water": Color changed from to Number of Drops of HCl added to "buffer": Color changed from to to Number of Drops of NaOH added to "water": Number of Drops of NaOH added to "buffer": _Color changed from Color changed from to Part Two: Titration Results for Acid-Base Neutralization (record the results from the...
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please help me answer 1-3. My avergae number of mL of 0.100M
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is 1.08mL.
CAMERY Review Layout References Mailings Wednesday, March 25, 2020 View Help ID Number Experiment 17: Analysis of an Antacid Normally in the lab we would do the titration as described. Instead I will be providing you with the results as if you had gotten them from your titration. The procedure calls for you to...
I MAINLY NEED HELP ON TABLES
PLS HELP THANK YOU
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC2H4O4, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 mL water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the...
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Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
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