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Previous Problem Problem List Next Problem (1 point) The data set below shows a sample of student exam scores on a final examination. 70, 60, 64, 83, 34, 41, 61, 55, 78, 61, 45, 66, 32, 75, 48, 91, 46, 89, 98, 60, 83, 55, 37, 71, 90 - Part 1 Compute the following, give each answer to at least four decimal places. The mean of these scores is 63.72 The standard deviation of these scores is 18.9814 Part 2 In this data set Scores below EEwould be considered unusually low Scores above would be considered unusually high. Preview My AnswersSubmit Answers You have atempted this probiem 4 tmes
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X(X-X)(X- X) 6.28 39.4384 3.72 13.8384 70 60 64 83 4 -29.72 883.2784 0.28 0.0784 19.28 371.7184 -22.72 2.72 516.1984 7.3984 8.72 76.0384 14.28 203.9184 61 78 61 45 2.72 7.3984 18.72 350.4384 5.1984 31.72 1006.158 11.28 127.2384 15.72 247.1184 27.28 744.1984 2.28 32 75 48 91 46 -17.72 313.9984 8925.28639.0784 98 34.281175.118 60 83 3.72 13.8384 19.28 371.7184 8.72 76.0384 37 26.72713.9584 7.28 52.9984 90 26.28690.6384 8647.04 71 Total 1593Part -1: 2x 1593 Mean 63.72 25 = 8647.04 360.2933 Variance = nї Σ(X-X). 25-1 ( Standard deviation-Variance-360.2933 8647.04)The Z-score more than 2 usually considered unusual high Now, we have to calculate the corresponding X (Scores) whose z value is 2 x-63.72 18.9814 2= 一 2 (18.9814) x-63.72 37.96279-x-63.72 37.96279 63.72-x X=101.6828 Hence, sores above 101.6828 would be considered unusually high.

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