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Using Hydrostatic Equilibrium, calculate the density at the center of the Sun (r=0).

Using Hydrostatic Equilibrium, calculate the density at the center of the Sun (r=0).

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Answer #1

By hydrostatic law

dP 2

rS 2 Ro

Pc = pressure at center of sun = 340 billion atm = 3.4 x 10^16 Pa .... google search

and Ro = radius of sun = 7 x 10^8 m

p = 3.4x10^16 x 7x10^8 / (6.67x10^-11 x 2x10^30)

= 178410 kg/m^3

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