The table shows the distribution of household sizes in the United States for a recent year.
|
x |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
|
P(x) |
0.281 |
0.340 |
0.154 |
0.129 |
0.060 |
0.022 |
0.013 |
Find:
a)The mean
b)The variance
c) The Standard deviation
D) the expected value

The table shows the distribution of household sizes in the United States for a recent year....
2) For the given probability Distribution, Complete the table and finds the mean, Variance and standard Deviation of the probability Distribution: (5 Points) P(x) 0.686 1 0.195 0.077 2 0.022 4 0.013 5 0.007 Variance: Standard Deviation: Mean: henning for themselves You
Recent research suggests that car ownership may have peaked. The following probability distribution table shows the random variable, x, where x is number of cars owned by household: x p (x) 0 0.10 1 0.27 2 0.40 3 0.18 4 0.05 Determine the mean of x. (b) Determine the standard deviation of x.
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Recent research suggests that car ownership may have peaked. The following probability distribution table shows the random variable, x, where x is number of cars owned by household: x p(x) 0 .10 1 .27 2 .40 3 .18 4 .05 Determine the mean of x (Round the answer to two decimal places). . (b) Determine the standard deviation of x. (Round the answer to two decimal places)
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1. The following probability distribution represents the number of people living in a Household (X), and the probability of occurrence (P(X)). Compute the Expected Value (mean), the Variance and the Standard Deviation for this random variable. Show Your Calculations for the Mean. X 1 2 3 4 5 P(X) .33 .29 .27 .07 .04 2. Use the binomial formula to compute the probability of a student getting 8 correct answers on a 10...