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An electric field of 10.2 N/C directed due north is superposed on an existing electric field...

An electric field of 10.2 N/C directed due north is superposed on an existing electric field of 16.7 N/C directed due east. What is the magnitude of the resultant field? What is the the direction of the resultant field as measured from the positive x-axis (East)?

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Answer #1

Both the fields are perpendicular to each other so the resultant field will be equal to thesquare root of the sum of the square of both the numbers ie. 19.57 N/C.mhidude

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