Let x be the distance he ran from A
the time taken in running this distance
t1 = x/9
The width of the lake = 4 miles = 6.4 km
The lenght along the lake = 5 mil = 8km
where swimming starts is (8-x) km
Using pythagoras theorem will give distance of swimming
t2 =
/ 3
t = t1 + t2
= x/9 +
/3
to make this time minimum, we use principle of minima
dt/dx = 0
1/9 - 2(8-x)/6
= 0
solving for x in calci
x = 7.947 km
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