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Extra 2.6.07 (Multistep) Use the exact values you enter to make later calculations. Push down, from...
"Extra 2.6.07 (Multistep) Use the exact values you enter to make later calculations. Push down, Relaxed ; length release from rest A spring has a relaxed length of 29 cm (0.29 m) and its spring stiffness is 6 N/m. You glue a 76 gram block (0.076 kg) to the top of the spring, and push the block down, compressing the spring so its total length is 16 cm. You make sure the block is at rest, then at time t...
A spring has a relaxed length of 36 cm (0.36 m) and its spring stiffness is 9 N/m. You glue a 83 gram block (0.083 kg) to the top of the spring, and push the block down, compressing the spring so its total length is 19 cm. You make sure the block is at rest, then at time t = 0 you quickly move your hand away、The block begins to move upward, because the upward forc.e on th€ block by...
STEP 1 Force: Just after releasing the block, calculate the force exerted on the block by the spring, the force exerted on the block by the Earth, and the net force: spring,r# 2.64 Earthy-6769 net.y - 1.96 0.676N 1.96 N Momentum update: Just after releasing the block, the momentum of the block is zero. Approximate the average net force during the next timel by the force you just calculated. At t0.07 seconds, what will the new momentum and velocity of...
Use the exact values you enter to make later calculations. A group of students performed the same "Newton's Second Law" experiment that you did in class. For this lab, assume g = 9.81 m/s2. They obtained the following results: m1(kg) t1(s) v1(m/s) t2(s) v2(m/s) 0.050 1.2000 0.2500 1.7279 0.5177 0.100 1.2300 0.3240 1.6064 0.7186 0.150 1.1500 0.3820 1.4591 0.9120 0.200 1.1100 0.4240 1.3806 1.0839 where m1 is the value of the hanging mass (including the mass of the hanger), v1...
Use the exact values you enter to make later calculations. A group of students performed the same "Newton's Second Law" experiment that you did in class. For this lab, assume g = 9.81 m/s2. They obtained the following results: m1(kg) t1(s) v1(m/s) t2(s) v2(m/s) 0.050 1.2000 0.2500 1.8108 0.3849 0.100 1.2300 0.3240 1.6360 0.6412 0.150 1.1500 0.3820 1.4768 0.8120 0.200 1.1100 0.4240 1.3935 1.0067 where m1 is the value of the hanging mass (including the mass of the hanger), v1...
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Use the exact values you enter to make later calculations A ray of light strikes a flat, 2.00-cm-thick block of glass (n-1.67) at an angle of θ-40.0° with respect to the normal (see figure below). 2.00 cm (a) Find the angle of refraction at the top surface and the angle of incidence at the bottom surface. 6 638 Your response differs from the correct answer by more than 10%. Double check your calculations. (b) Find the...
Use the exact values you enter to make later calculations. A uniformly accelerated car passes three equally spaced traffic signs. The signs are separated by a distance d = 21 m. The car passes the first sign at t = 1.3 s, the second sign at t = 3.7 s, and the third sign at t = 5.5 s. (a) What is the magnitude of the average velocity of the car during the time that it is moving between the...
Problem 3.29 Astar ofmass 6 x1000 kg is located at <6 x ío» 5x10a, o> m. A planet of mass 9 × iO24 kg s located at eston 10x10ao, m and is me 0> m/s. yofea nofil nr. ng w haves (a) During a time interval of 1 10 seconds, what is the change in the planet's velocity? m/s (b) During this time interval of 1 x 106 seconds, what is the change in the planet's position? (e) why are...
Problem 3.29 A star of mass 6 x 1030 kg is located at <6 x 1012, 4 x 1012, 0> m. A planet of mass 2 x 1024 kg is located at <5 x 1012, 9 x 1012, 0> m and is moving with a velocity of <0.5 x 104, 1.4 x 104, 0> m/s. (a) During a time interval of 1 x 10° seconds, what is the change in the planet's velocity? > m/s (b) During this time interval...