Question

A strip of invisible tape 0.12 m long by 0.013 m wide is charged uniformly with a total net charge of 5 nC (nano = 1e-9) and is suspended horizontally, so it lies along the x axis, with its center at the origin, as shown in the diagram.
Calculate the approximate electric field at location < 0, 0.03, 0 > m (location A) due to the strip of tape. Do this by dividing the strip into three equal sections, as shown in the diagram, and approximating each section as a point charge.




A) What is the approximate electric field at A due to piece #1?
_____N/C

C) What is the approximate electric field at A due to piece #3?
_____N/C

**I'm pretty sure that both A and C are the same answer but i'm just not sure as to how to go about answering it. I've been able to answer part B which is:

B) What is the approximate electric field at A due to piece #2?
<0,16700,0>N/C

Steps to B:

= ( (9e9)* (1.67e-9) ) / (0.03²) =<0,16700,0>

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Answer 1

The electric field at A due to piece 1 is given by the formula, From figure, E and E, along A is given by, - Sin Substitute the above two values in the equation E - Ei+ Ej 9x1091 5x10-9 0.12 0.12 (4.8x10+(3.6x10'))N/C The magnitude of electric field is given by, E-48x10'(3.6x10) N/C -6x103 Nc Therefore, the approximate electric field at A due to piece 1 is 6x10* N/C

The electric field at A due to piece 2 is given by, 9x10 5x10-9 (0.03) (1.6x10*)jN/C Therefore, the approximate electric field at A due to piece is (1.6x10*) j NC 9x10 5x10-9 (0,12-(0.03)j 0.12 +(0.03 (4.8x10(3.6x10'))NC The magnitude of electric field is given by, E,-'(4.8x103) +(-3.6x 103).NC -6x103 N/C Therefore, the approximate electric field at A due to piece 3 is 6x10* N/C