
Please answer in vector format! Thanks!!
a) Charge of the piece = 4/3 *10^-9 C = 1.333e-9 C
distance of the midpoint from origin = 0.17/3 m = 0.0567 m
Electric field at A = kq/r^2
= 9e9*1.333e-9/[0.0567^2 +0.09^2] *0.0567/sqrt[0.0567^2 +0.09^2] i + 9e9*1.333e-9/[0.0567^2 +0.09^2] *0.09/sqrt[0.0567^2 +0.09^2] j
= 565 i + 897j
Hence field is (565, 897, 0) N/C
b) Charge of middle piece = 4/3 *10^-9 C = 1.333e-9 C
distance of the midpoint from origin = 0 m
Electric field at A = kq/r^2
= 9e9*1.333e-9/[ 0.09^2]
=1481 j N/C
Hence field is (0, 1481, 0) N/C
part c) because of symmetrical to part a
E = (-565, 897, 0) N/C
part d) Enet= [(565+0-565), (897+1481+897) , 0]
= [ 0 , 3275 , 0 ] N/C
Please answer in vector format! Thanks!! A strip of invisible tape 0.17 m long by 0.011...
A strip of invisible tape
0.13 m long by 0.011 m wide is charged uniformly with a total net
charge of 4 nC (nano = 1 ✕ 10−9) and is suspended horizontally, so
it lies along the x axis, with its center at the origin, as shown
in the figure below. Calculate the approximate electric field at
location 0, 0.02, 0 m (location A) due to the strip of tape. Do
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Problem 15.28 (Multistep) A strip O invisible tape 0.15 m ong by 0.017 m wide is charged uniformly with a total net charge of 5 nC nano = 1 x 10 9 and is suspended horizontally, so it lies along the x axis, with its center at the ongin, as shown in the gure below. Calculate the approximate electric field at location <0, o.07, 0> m (location A) due to the strip of tape. Do this by dividing the strip...
Problem 15.28 (Multistep) A strip of invisible tape 0.15 m long by 0.017 m wide is charged uniformly with a total net charge of 5 nC (nano 1 x10- and is suspended horizontally, so it lies along the axis, with its center at the origin, as shown in the figure below. Calculate the approximate electric field at location <0, 0.07, 0> m (location A) due to the strip of tape. Do this by dividing the strip into three equal sections,...
A strip of invisible tape 0.12 m
long by 0.013 m wide is charged uniformly with a total net charge
of 5 nC (nano = 1e-9) and is suspended horizontally, so it lies
along the x axis, with its center at the origin, as shown in the
diagram.
Calculate the approximate electric field at location < 0, 0.03,
0 > m (location A) due to the strip of tape. Do this by dividing
the strip into three equal sections, as...
A strip of invisible tape 0.16 m long by 0.015 m wide is charged uniformly with a total net charge of 5 nC (nano = 1e-9) and is suspended horizontally, so it lies along the x axis, with its center at the origin, as shown in the diagram.Calculate the approximate electric field at location < 0, 0.03, 0 > m (location A) due to the strip of tape. Do this by dividing the strip into three equal sections, as shown in the diagram, and approximating each section as...
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