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Problem 1. Let A event from outcome space S,equipped with probability function I . Prove that P(A) 1. Hint: You can use theorem 1.4 Problem 2. Let A,B,C events from outcome space S, equipped with probability function P. Prove that P(AUBUC)- P(A)+P(B)+P(C)- PAnB) PAnC) PBnC) +P(AnBnc) Hint: You can treat A and BUC as two events and apply theorem 1.6. You will also need to use Law 5 from the distributive laws.

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2.

Let A,B,C events from outcome Space S, LHS P(AU Buc)-PA(BUC) -P(A)+P(BuC)-P[An(BC)) since addition theorem for two events P(A)+P(BuC)-P((An B)U(AUC)) since distributive law -P(A)+LP(B)+P(C)-P(Bnc)-PAB)+P(Anc)-P((AnB)n(Anc)] since addition theorem for two events -P(A) + P (B) + P(C)-P(BAC)-P (AnB)-P(Anc) + P (AnBnC)

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Let A be the an event in S A be the compliment of A since AUA =S P(A)-1-(A > P(A) 1 (Using non negativity) By using these 3 axioms we can also prove ary other properties of probability.

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