Question

I have problem regarding how to plot a equilibrium line. I have a equilibrium relation yA=2.53xA. How do it plot such a line?

Answer 1

The equilibrium relation as stated is

y * A = 2.53 * X * A ..... (1)

Dividing (1) by A on both sides

y * A / A = 2.53 * X * A /A  

Hence

y = 2.53 * X ..... (2)

This is a linear equation of the form y = m* X + C ........... (3)

where m = slope of the linear line and C = intercept on y axis

Comparing equation (3) with equation (2) we get

m = slope of linear line = 2.53 and Intercept on Y axis = C = 0. A probable graph is shown below.

Y M slope 2.53 С-0 х