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You have a parallel-plate 5.17 × 10-6 F capacitor that is charged to 0.00871 C. While...

You have a parallel-plate 5.17 × 10-6 F capacitor that is charged to 0.00871 C. While the capacitor is isolated, you change the plate separation so that the capacitance becomes 1.89 × 10-6 F. How much work do you perform in this process?

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Answer #1

C, 5.17 x106 F 2 2 C Co- 2 C2 2 2 C 2 = (8-7) X103 )2 1.89 5。17 -758641×166(0-335677 2×10 1 2 .732丁 12 732 Jaule

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