Question

To use the relationships among an applied load, internal shear force, and bending moment to draw the variation of shear and moment in a beam without writing equations and plotting points. You will need to know that dMdx=V and dVdx=w(x) and know how to take derivatives and integrate expressions.

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Part A - Draw the shear diagram

Given the beam and its corresponding free-body diagram, draw the shear diagram.

Begin by placing vertical lines. Then place segments between the lines. NOTE - You should not draw an

Answer 1

Take moment about the point B. R x16+12+1x -C R-1.25 kN -1.25 kN() Apply vertical equilibrium condition. -1.25+R, 1x4 R, 5.25 kN Calculate the shear force as follows: V1.25kN() VC1.25 kN() ,Nge =1.25 kN(4) V,ie =-1.25+5.25 -4 kN() V -0 Calculate the moment as follows M 0 Mcig Rx8 =-1.25 x8 =-10 kN- m McLee R,x8+12 --1.25x8+12 =2 kN m MAg Rx16+12 =-125x16+12 =-8 kN m ML Rx16+12 --1.25x16+12 =-8 kN. m M 0 1.25 kN 0 ft ft 16 ft 8 ft S.ED 4 kN 2 kN m -8 kN m -10 kN. m B.M.D