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answer) when the student goes upstream his relative speed is =1-0.5=0.500m/s
so t=distance/speed=1650m/0.500m/s=3300s
when going downstream the speed of the student is =1.00+0.500=1.500m/s
so t=1650/1.5=1100s
so the whole trip takes=3300+1100=4400s=answer
in still water the total time=3300/1=3300s
the difference=3300-4400= -1100s=answer
If the number is a decimal please include 4 digits past the decimal point if available....
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A river has a steady speed of 0.500 m/s. A student swims upstream a distance of 2.00 km and swims back to the starting point. If the student can swim at a speed of 1.20 m/s in still water, how long does the trip take?
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please show how to get answer for a), b), c).
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If the number is a decimal
please include 4 digits past the decimal point if available.
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If the number is a decimal
please include 4 digits past the decimal point if available.
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If the number is a decimal
please include 4 digits past the decimal point if available.
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If the number is a decimal please include 4 digits past the
decimal point if available.
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If the number is a decimal
please include 4 digits past the decimal point if available.
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If the number is a decimal
please include 4 digits past the decimal point if available.
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