Question

18. c Sand is converted to pure silicon in a three step process. The third step is: SiCl4(g) + 2Mg(s) 2MgCl2(s) + Si(s) AH= -
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer -

Given,

\DeltaG = -625.6 kJ

Moles of SiCl4=25 mol

Enthalpy change = ?

SiCl₄ (g) + 2Mg (s) → 2MgCl₂ (s) + Si (s)

Mole of Enthalpy change = -625.6 kJ/ mol

So, For 25 mole of Enthalpy change = -625.6 kJ/mol * 25 mol

Enthalpy change = -15640 kJ or -1.5 *104 kJ [Answer]

Add a comment
Know the answer?
Add Answer to:
18. c Sand is converted to pure silicon in a three step process. The third step...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • I understand if reaction is reversed, you change the sign but how to you know to...

    I understand if reaction is reversed, you change the sign but how to you know to reverse the reaction? In the problem, Sand is converedto pure silicon in a 3 step process. The final step in this process is as follows: SiCl4 (g) + 2Mg (s) --> 2MgCl (s) + Si (s) ChangeHrxn=6256kj/mol What is the enthalpy change if 25.0 mol of silicon tetrachloride is converted to elemental silicon? I get the answer by 25 mol SiCl4 x 6256kj/mol=15640kj but...

  • #9-12 A simple step by step process for all please Thank you! a) -2.81 x 103...

    #9-12 A simple step by step process for all please Thank you! a) -2.81 x 103 kJ b) -25.8 k c15.6 k d) -42.6 k e) 25.8 k Given the thermochemical equation calculate AHo for the following reaction: 9. 2NOg) + 028) 2NO2g) 솨1°=-114.0 kJ NOg) NO(g) 1/2 02(g) a) +114.0 k b) +57.0 k c) -114 kJ d) -57.0k) e) +128 k] 10. The standard enthalpy change for the following reaction is -72.8 kJ. What is the standard enthalpy...

  • Problem 3 please I'm not understanding. Please tell how you got the answer step by step...

    Problem 3 please I'm not understanding. Please tell how you got the answer step by step and the equation used ! Thanks Date 1. Calculate AE for a system undergoing an endothermic process in which 25.3 kJ of heat flows and where 4.6 kJ of work is done on the system. 2. Calculate the work associated with the compression of a gas from 52 L. to 33 L at a constant external pressure of 16 atm. 3. How many grams...

  • 3. Impure nickel, refined by smelting sulfide ores in a blast furnace, can be converted into...

    3. Impure nickel, refined by smelting sulfide ores in a blast furnace, can be converted into metal from 99.90% to 99.99% purity by the Mond process. The primary reaction involved in the Mond process is: (-25 points total; -5 points each) Ni(s) + 4 CO(g) Ni(CO)4(8) a. The spontaneity of the above reaction is temperature dependent. Given the following values and those in the Appendix in your book, calculate Hº and ASº for the above reaction. [AH °(Ni(CO).) = -607...

  • only questions number: #3,6,8,16,19,22 Δι CH 122 - Practice Problems for Chapter 12 Do NOT use...

    only questions number: #3,6,8,16,19,22 Δι CH 122 - Practice Problems for Chapter 12 Do NOT use this problem set solely as test preparation. This problem set does NOT cover everything that we have discussed in class. You will still need to study class materials in order to do well on the learning assessment. 1. Of the following all are valid units for a reaction rate except A. moll B. M/S C. molhr D.g's E.molle 2. Which one of the following...

  • (6 pts.) 1. The air pressure in the inner tube of a tire on a typical...

    (6 pts.) 1. The air pressure in the inner tube of a tire on a typical racing bike is held at a pressure of 115 psi (pounds! per square inch). Convert this pressure to atm and mm Hg. (3 pts. each) The atmospheric pressure is 0.978 atm. Determine the pressure of the enclosed gas in each of the cases depicted below. Gas Gas (6 pts.) 3. A 5.90 L bottle contains 1070 g of oxygen at 25.0°C. Calculate the pressure...

  • 4. Only ideal processes can be thermodynamically "reversible." Why can rear proce y can real process...

    4. Only ideal processes can be thermodynamically "reversible." Why can rear proce y can real processes not be? 5. Consider the following reactions. (Note: if this were an exam we would give you an excerpt on tabular data from Appendix 4 (Table A4.3). 2Fe(s) + 3Cla(s) 2FeCl(s) N2H4(8) + H2(g) + 2NH3(g) (a) Would you expect the entropy change for the above reaction to be >0, <0, or no (small)? Justify your answer. (d) Would you expect the entropy change...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT