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A sinusoidally varying voltage is represented by

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Answer #1

Comparing given equation with standard equation:

V(t) = V_max*sin (w*t)

V_max = Peak Voltage

w = Angular frequency = 2*pi*f

f = frequency = w/(2*pi)

Now From above given equation:

V(t) = (62.5 V)*sin (170t)

71

So

Part A

frequency = f = 170*pi/(2*pi) = 85 Hz

Part B.

V_max = Peak Voltage = 62.5 V

Please Upvote.

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Answer 1

Comparing given equation with standard equation:

V(t) = V_max*sin (w*t)

V_max = Peak Voltage

w = Angular frequency = 2*pi*f

f = frequency = w/(2*pi)

Now From above given equation:

V(t) = (62.5 V)*sin (170t)

71

So

Part A

frequency = f = 170*pi/(2*pi) = 85 Hz

Part B.

V_max = Peak Voltage = 62.5 V

Please Upvote.