Consider the initial value problem
(a) Evaluate both
(b) Finally, show that y(t) is a solution of 21. Why doesn't this example contradict Theorem 7.16?
Definition 1.15:
A first order differential equation together with an initial condition,
Is called an initial value problem. A solution of the initial value problem is a differentiable function y(t) such that
1.
for all t in an interval containing
where y (t) is defined, and
2. 
THEOREM 7.16 Uniqueness of solutions
Suppose the function f (t, x) and its partial derivative ∂f/∂x are both continuous on the rectangle R in the tx-plane. Suppose
and that the solutions
Then as long as (t, x(t)) and (t, y(t)) stay in R, we have
x(t) = y(t).
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