Show that
is a solution of the initial value problem
, where y(0) = 0, in the sense of Definition 1.15 from Section 2.1. Find a second solution and explain why this lack of uniqueness does not contradict Theorem 7.16.
Definition 1.15:
A first order differential equation together with an initial condition,
Is called an initial value problem. A solution of the initial value problem is a differentiable function y(t) such that
1.
for all t in an interval containing
where y (t) is defined, and
2. 
THEOREM 7.16 Uniqueness of solutions
Suppose the function f (t, x) and its partial derivative ∂f/∂x are both continuous on the rectangle R in the tx-plane. Suppose
and that the solutions
Then as long as (t, x(t)) and (t, y(t)) stay in R, we have
x(t) = y(t).
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