(Civil eng.) Modify the program written for Exercise to determine the maximum load that can be placed at the end of an 8-foot I-beam, shown in Figure, so that the stress on the fixed end is 20,000 lbs/in2. Use the fact that this beam’s rectangular moment of inertia is 21.4 in4 and the value of c is 3 in.
Figure: Calculating an I-beam’s maximum load

Exercise:
(Civil eng.) The maximum load that can be placed at the end of a symmetrical wooden beam, such as the rectangular beam shown in Figure, can be calculated as the following:

L is the maximum weight in lbs of the load placed on the beam.
S is the stress in lbs/in2.
I is the beam’s rectangular moment of inertia in units of in4.
d is the distance in inches that the load is placed from the fixed end of the beam (the “moment arm”).
c is one-half the height in inches of the symmetrical beam.
For a 2” × 4” wooden beam, the rectangular moment of inertia is given by this formula:

c = ½(4 in) = 2 in
a. Using this information, design, write, compile, and run a C++ program that computes the maximum load in lbs that can be placed at the end of an 8-foot 2” × 4” wooden beam so that the stress on the fixed end is 3000 lb/in2.
b. Use the program developed in Exercise a to determine the maximum load in lbs that can be placed at the end of a 3” × 6” wooden beam so that the stress on the fixed end is 3000 lbs/in2.
Figure: Calculating a symmetrical wooden beam’s maximum load

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