(Mechanics)
a. The increase in length of a rectangular slab of metal that’s fixed at one end and pulled by a force at its other end is given by this formula:
I = F × k × l / (w × d × ε)
I is the increase in length (mm).
F is the applied force (N = kg-m/s2).
k is 1000 (conversion of F to millimeter units).
l is the bar’s length (mm).
w is the bar’s width (mm).
d is the bar’s depth (mm).
ε is the metal’s modulus of elasticity (N/mm2).
Given this information, design, write, compile, and run a C++ program to calculate the increase in length when a slab of aluminum that’s 3 meters long, 4 cm wide, and 2 mm deep is subjected to a force of 4 Newtons. Aluminum’s modulus of elasticity is 68,950 N/mm2. (Hint: Make sure to convert the length and width to mm dimensions.) Verify the result produced by your program with a hand calculation.
b. After verifying that your program is working correctly, use it to determine the increase in length for a slab of copper having the same dimensions as the aluminum slab described in Exercise a. Copper’s modulus of elasticity is 110,000 N/mm2.
We need at least 10 more requests to produce the solution.
0 / 10 have requested this problem solution
The more requests, the faster the answer.