The loop equation for the circuit in Fig. 3.48 is:
(a)−10 + 4i + 6 + 2i = 0
(b) 10 + 4i + 6 + 2i = 0
(c) 10 + 4i – 6 + 2i = 0
(d) −10 + 4i – 6 + 2i = 0

Answer: 3.6a
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