Two spheres of the same diameter (in air), one made of a lead alloy the other one made of steel are submerged at a depth h = 2000. m below the surface of the ocean. The ratio of the volumes of the two spheres at this depth is V steel (h)/V Lead (h) = 1.001206. Knowing the density of ocean water ρ = 1024 kg/m3 and the bulk modulus of steel, B Steel = 160 • 109 N/m2, calculate the bulk modulus of the lead alloy used in the sphere.
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