Question

1) In a ruby laser, light is produced in a solid rod of ruby, with refractive index 1.77. The light emerges from the end of the rod into the surrounding air. Part A At what angle should the rod end be cut so the emerging light is fully polarized?

2)

A beam of white light is incident on the surface of a diamond at an angle θa. (Figure 1) Since the index of refraction depends on the light's wavelength, the different colors that comprise white light will spread out as they pass through the diamond. For example, the indices of refraction in diamond are nred=2.410for red light and nblue=2.450 for blue light. Thus, blue light and red light are refracted at different angles inside the diamond, as shown in the picture. The surrounding air has nair=1.000. Note that the angles in the figure are not to scale.

Part A Now consider θc, the angle at which the blue refracted ray hits the bottom surface of the diamond. If θc is larger than the critical angle θcrit, the light will not be refracted out into the air, but instead it will be totally internally reflected back into the diamond. Find θcrit. Express your answer in degrees to four significant figures. θcrit = 24.09   ∘   SubmitHintsMy AnswersGive UpReview Part Correct Part B A diamond is cut such that the angle between its top surface and its bottom surface is α. For α=45∘, find the largest possible value of the incident angle θa such that the blue light is totally internally reflected off the bottom surface. Express your answer in degrees to four significant figures. θa =   ∘   SubmitHintsMy AnswersGive UpReview Part Provide FeedbackContinue

Figure 1 of 1

Answer 1