Question

Write a program that uses a structure to store the following data about a customer account: Name Address City, state, and ZIP Telephone number Account Balance Date of last payment The program should use an vector of at least 20 structures. It should let the user enter data into the vector, change the contents of any element, and display all the data stored in the array. The program should have a menu-driven user interface. Input Validation: When the data for a new account is entered, be sure the user enters data for all the fields. No negative account balances should be entered.

Answer 1

#include

#include

using namespace std;

struct customer{ //customer structure datatype

string name, address, city, state, zip, telephone, date;

int balance;

};

void setCustomer(customer&); //inputs customer data from user

void getCustomer(customer); //prints customer data to the screen

int main()

{

int size,action=1;

cout<<"-+- Customer Manager -+-\nHow many customers?:\t";

cin>>size;

customer*database=new customer[size];

cout<<"\n --- Created database of "<

while(action!=0){ //Menu Interface Loop

cout<<"-+- Menu -+-\n 0: Quit\n 1: Set a customer's information\n 2: Display a customer's information\n\n>";

cin>>action;

cout<

switch(action){

case 1:{

int cnum;

cout<<"customers:\n";

for(int x=0;x

cout<

cout<<"\ncustomer number to change:\t";

cin>>cnum;

if(cnum<=size && cnum>0)

setCustomer(database[cnum-1]);

else

cout<<"\ninvalid customer number!\n\n";

}

break;

case 2:{

int cnum;

cout<<"customers:\n";

for(int x=0;x

cout<

cout<<"\ncustomer number to display:\t";

cin>>cnum;

if(cnum<=size && cnum>0)

getCustomer(database[cnum-1]);

else

cout<<"\ninvalid customer number!\n\n";

}

break;

default: break;

}

}

delete[] database;

return 0;

}

void setCustomer(customer&set)

{

cout<<"Enter Data for the Customer:\nName:\t\t\t";

cin>>set.name;

cout<<"Address:\t\t";

cin.ignore(256,'\n');

getline(cin, set.address);

cout<<"City:\t\t\t";

cin>>set.city;

cout<<"State:\t\t\t";

cin>>set.state;

cout<<"Zip Code:\t\t";

cin>>set.zip;

cout<<"Telephone Number:\t";

cin>>set.telephone;

cout<<"Date of last Payment:\t";

cin>>set.date;

do{

cout<<"Account Balance:\t";

cin>>set.balance;

if(set.balance<0)

cout<<"Invalid Balance!\n";

}while(set.balance<0); //data validation

}

void getCustomer(customer get)

{

cout<<"\n --- Data for "<

cout<<"\nAddress:\t"<

cout<<"\nTelephone:\t"<

cout<<"\nLast Payment:\t"<

cout<<"\nAccount balance:\t"<

}

Answer 2

Follow : http://www.dreamincode.net/forums/topic/80834-struct-with-arrays-in-functions/

Answer 3

#include 002 #include 003 #include 004 005 006 using namespace std; 007 008 void menu(); 009 void acc(string ,int AcArray[30]); //c for customer number. 010 void display(string , int AcArray[30]); 011 void editBalance(string,int AcArray[30]); 012 void displayBalance(); 013 014 015 struct customer 016 { 017 string name; 018 string address; 019 string city; 020 string state; 021 string zip; 022 string tele; 023 //double acc; 024 char date[20]; 025 double balance; 026 027 }; 028 029 030 031 int main(int argc, char *argv[]) 032 { 033 const int MaxAccounts = 30; 034 int customer AcArray[MaxAccounts]; 035 036 menu; 037 038 editBalance( AcArray, MaxAccounts ); 039 040 displayBalance( AcArray, MaxAccounts ); 041 042 043 044 system("PAUSE"); 045 return EXIT_SUCCESS; 046 } 047 048 void menu 049 { 050 int choice; 051 //char YN; 052 053 cout << "Welcome to you bank company that has lost all your money. " << endl; 054 sleep(1000); 055 cout << "Please choose an action from the menu displayed below." << endl; 056 cout << "Press 1 to enter a new account(s)." << endl; 057 cout << "Press 2 to see current balance." << endl; 058 cout << "Press 3 to edit current balance." << endl; 059 cout << "Press 4 to exit." << endl; 060 cin >> choice 061 062 switch(choice) 063 { 064 case 1: 065 acc; 066 break; 067 068 case 2: 069 cout << "current account balances are " << customer[c].acc << endl; 070 bool more() 071 { 072 cout << "Continue (y/n) ? "; 073 int reply = cin.get(); 074 return !(reply=='n' || reply=='N'); 075 } 076 break; 077 078 case 3: 079 editBalance; 080 break; 081 082 case 4: 083 return 0; 084 break; 085 086 } 087 } 088 089 double acc(customer AcArray[], const int MaxAccounts ) 090 { 091 //int c; 092 int total; 093 //char YN; 094 095 cout << "How many customers would you like to enter?" << endl; 096 cin >> total; 097 098 for(int c = 0; c < total; c++) 099 { 100 cout << "Enter the name( First Last) of customer " << total; 101 cin >> AcArray[c].name; 102 //validate 103 104 cout << "Enter the adress(i.e. 4758 nw 0 st) of customer " << total; 105 cin >> AcArray[c].address; 106 //validate 107 108 cout << "Enter the city(i.e. Florida) of customer " << total; 109 cin >> AcArray[c].city; 110 //validate no numbers 111 112 cout << "Enter the state(i.e. FL) of customer " << total; 113 cin >> AcArray[c].state; 114 //validate 2 letters only! 115 116 cout << "Enter the 5 digit zip code(i.e.12345) of customer " << total; 117 cin >> AcArray[c].zip; 118 //validate 5 numbers 119 120 cout << "Enter the telephone number(ie. 123-456-7890) of customer " << total; 121 cin >> AcArray[c].tele; 122 //validate no letters. 123 124 cout << "Enter the current account balance of customer " << total; 125 cin >> AcArray[c].balance; 126 //validate double && non-neg 127 128 cout << "Enter the Date(i.e. 11 05 2009) of the last payment of customer " << total; 129 cin >> AcArray[c].date; 130 //validate 131 } 132 /* cout << endl; 133 cout << "Would you like to return to the menu(y or n): "; 134 cin >> YN*/ 135 136 bool more() 137 { 138 cout << "Continue (y/n) ? "; 139 int reply = cin.get(); 140 return !(reply=='n' || reply=='N'); 141 } 142 143 144 } 145 146 147 void display(string, int c, int AcArray[]) 148 { 149 for(int c = 0; c < total; c++) 150 { 151 152 cout << "Customer " << c << " account information: " << endl; 153 cout << endl; 154 cout << "The customer's name is " << AcArray[c].name << endl; 155 cout << AcArray[c].name <<"'s address is " << AcArray[c].address << endl; 156 cout << AcArray[c].name <<" is currently living in the city " << AcArray[c].city << endl; 157 cout << AcArray[c].name <<" is currently living in the state of " << AcArray[c].state << endl; 158 cout << AcArray[c].name <<"'s zip code is " << AcArray[c].zip << endl; 159 cout << AcArray[c].name <<"'s telephone number is " << AcArray[c].tele << endl; 160 cout << AcArray[c].name <<"'s current account balance is " << AcArray[c].balance << endl; 161 cout << "The last day "<< AcArray[c].name <<" paid was " << AcArray[c].date << endl; 162 163 } 164 switch(YN) 165 { 166 case y: 167 menu; 168 break; 169 170 case n: 171 return 0; 172 } 173 } 174 175 void editBalance( account AcArray[], const int MaxAccounts ) //Display each account seperaetely 176 { 177 for( int c = 0; c < MaxAccounts; c++ ) 178 AcArray[c].balance = c; 179 } 180 181 void displayBalance( account AcArray[], const int MaxAccounts ) 182 { 183 for( int c = 0; c < MaxAccounts; c++ ) 184 cout << AcArray[c].balance; 185 186 bool more() 187 { 188 cout << "Continue (y/n) ? "; 189 int reply = cin.get(); 190 return !(reply=='n' || reply=='N'); 191 } 192 }