Question

There is a gravitational redshift between a clock at sea level and a clock at the top of the (very tall) mountain K2. Imagine that you have two identical clocks, one at sea level and one at the top of K2. If they are both started on 2020 January 1, and both run until 2020 December 31, by how much (roughly) will their times differ at the end of the year? Give your answer in seconds. Which one will have run more quickly, and which more slowly?

Problem 2: There is a gravitational redshift between a clock at sea level and a clock at the top of the very tall) mountain K2. Imagine that you have two identical clocks, one at sea level and one at the top of K2. If they are both started on 2020 January 1, and both run until 2020 December 31, by how much (roughly) will their times differ at the end of the year? Give your answer in seconds. Which one will have run more quickly, and which more slowly?

Answer 1

Solh. - Given, Gravitational redshift between a clock at sea level (radius of earth, RE = 6378.1km) and at the top of (very Hall ) mountain Kz (her of kz from sea land, hy 8.611 km) Total time, 7 = 1 leap years t = 366 days Bilety Ry = 6378.1 km [From china Rhy = RE thes= (6378 1 + 2 Rics 6386.711 km [From center From the Schwarzschild mehi of corth) The interval differences that two height can be given as, 4 time Sea level Podius

7 T 63781 = 366 x 1- It 6386-711 Days = 13.439 Days = 13.439 x 24 x 60 x60 second = 1161135.733 second TI 3 ut So on increasing hight time spend fast, so the clock at kz will. run fast and the clock at sea lend will reun slower due to gravitational red shift.