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E'° of the NAD+/NADH half reaction is –0.32 V. The E'° of the Acetic acid/acetaldehyde half...

E'° of the NAD+/NADH half reaction is –0.32 V. The E'° of the Acetic acid/acetaldehyde half reaction is –0.58 V. What is the E'° of the spontaneous reaction?

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The reduction half-cell reaction is given by:- NAD+ + e + NADH, EO = -0.32 V ... (1) The oxidation half-cell reaction is givSince, total Eº is positive, so we have AG = -NFE = -0.26nF = negative ... (3) Where, AG = change in Gibbs free energy, F

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