Question

6. (16 points) Magnesium bromide reacts with silver nitrate to form silver bromide (solid) and magnesium sulfate (aq). A mixture of 50.0 8 of magnesium bromide (MM 184.1 g/mol) and 100 g of silver nitrate (MM- 169.9 g/mol) is allowed to react. Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete, Do by ICE Method Type of reaction Double displacement 2015 MgBra (5) + 2 AgNO,(aq) > Mg(NO)2(aq) 2 AgBr(s)

Answer 1

solution with te Magnesium Bronide & Silver nitrate - Silver hanside of magnesium can e sulphate Balanced equation Mg Bra + 2Ag Noz 2Ag Bo + Mg(NO₃)2 Using ICE Method Mg Brz (5)+ 2Ag No cacp). Mg(NO₃) Case + 2 Ag Br(s). 0.27 15ml / 0.5885 mil - 2x + 2x - 0. 2715 mol 1 mol My Br2 50 g of Mg Big & - 184. 1 glmol Imol AgNO3 = loog of my 321 169.9 glmol 0.5885 mol

molar mass of Casoa a. In hann 0.2715-x=0 8.5885-2x=0 K = 0. 2715 n=0.5885 -0.29 425 Smalleg taking the larger number ofx - Mg Boz (s) + 2 Ag NO₂ (aq) – Mg(No) (aq) + 2Ag Kr (S) I 0. 2715 8. 5885 +0-2715 +2(0.2419 -268-2415) -0. 2715 6429405 0. 0455 0-2415 0.543 read and is Mg B& because toir is • So the nothing limiting left. The exess s moles Complete reactant is of AgNo after the reaction the reaction is AgNO₃- and left when