The refractive index n of CH2I2 is 1.732 for 656 nm light. Its density at 20°C...

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Question

$The refractive index n of CH2I2 is 1.732 for 656 nm light. Its density at 20°C is 3.32 g.cm?. Calculate the distortion polari$

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Answer 1

Answer #1

The distortion polarizability ( $\alpha$ ₀) can be calculated as follows.

$\alpha$ ₀ = {( $\eta$ ² - 1)/( $\eta$ ² + 2)}*M/ $\rho$

Where 'M' is the molar mass of CH2I2 = 268 g/mol

And ' $\rho$ ' is the density of CH2I2 = 3.32 g/mL

i.e. $\alpha$ ₀ = {(1.732²-1)/(1.732²+2)}268 g.mol^-1/3.32 g.cm^-3

Therefore, $\alpha$ ₀ = 32.287 cm³/mol

Answer 2

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