Question

Hi. can some one please explain me the solution for this question. the correct answer is E. thanks.

10. How much bismuth is deposited in 1.60 hours by the electrolysis of a solution of NaBio, by a constant current of 0.55A? a) 6.86 g b) 3.43 g c) 2.298 d) 1.72 g e) 1.37 g

Answer 1

Hi Dear Friend, here we have to use Faraday's law of electrolysis

w = [ A * c * t ] / [ Z * F ]

w = mass of metal liberated or deposited;

A = atomic mass of metal (Bismuth) = 208.9804 g/mol ;

c = current in amperes = 0.55 A;

t = time in seconds = 1.60 hours = 5760 seconds;

Z = charge on metal (BiO₃^-) = +5 ; Bismuth is in +5 oxidation state in this compound

F = Faraday's constant = 96485 C/mol of electrons

w = [ A * c * t ] / [ Z * F ]

w = [208.9804 g/mol x 0.55 A x 5760 sec] / [ 5 x 96485 C/mol of electrons]

w = 1.37233747671 g

w = 1.37 g -------------------------------------- YOUR ANSWER

10. How much bismuth is deposited in 1.60 hours by the electrolysis of a solution of NaBio, by a constant current of 0.55A? #6.865 e) 1.37 g

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